Question

Answer 1

\(P=log_{2x}x=\dfrac{1}{x}\cdot log_2x=\dfrac{1}{x}\cdot3=\dfrac{3}{x}\)

Answer 2

\(log_2x=3\Rightarrow log_x2=\dfrac{1}{3}\)

\(P=log_{2x}x=\dfrac{1}{log_x2x}=\dfrac{1}{log_x2+log_xx}=\dfrac{1}{\dfrac{1}{3}+1}=\dfrac{3}{4}\)