Question

Answer 1

a: =3^11/3^10=3

b: =2^6*3^7/2^6*3^6=3^7/3^6=3

c: \(=\dfrac{2^5\cdot2\cdot5^5}{10^5\cdot10}=\dfrac{2}{10}=\dfrac{1}{5}\)

d: \(=\dfrac{2^6\cdot7^6\cdot7}{2^6\cdot7^6}=7\)

Answer 2

a/ kq =\(\dfrac{3^{11}}{3^{10}}\)=3

b/kq = \(2^6\cdot3^6\cdot3\)/6^6 = 6^6 x 3 / 6^6 = 3

c/ kq = 2^5 x 5^5 X 2 / 10^5 x 10 = 1/5

d/ kq = 2^6 x 7^6 x 7 / 14^6 = 7