Question

Answer 1

\(1,=\sqrt{6-2\sqrt{6}+1}\\ =\sqrt{\left(\sqrt{6}-1\right)^2}=\sqrt{6}-1\\ 2,=\sqrt{4-2.2.\sqrt{3}+3}-2\\ =\sqrt{\left(2-\sqrt{3}\right)^2}-2\\ =2-\sqrt{3}-2\\ =-\sqrt{3}\\ 3,=\left(2+\sqrt{3}\right)\sqrt{7-4\sqrt{3}}\\ =\left(2+\sqrt{3}\right)\sqrt{\left(2-\sqrt{3}\right)^2}\\ =\left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right)\\ =4-3\\ =1\)

Answer 2

Phần 5 đây,các phần khác lm tương tự nhá:)