Question

Answer 1

c: \(=\left(x^2-\dfrac{1}{4}\right)\cdot\left(4x-1\right)\)

\(=4x^3-x^2-x+\dfrac{1}{4}\)

d: \(=\left(2x^2+x-x-\dfrac{1}{2}\right)\left(3-\dfrac{1}{2}x\right)\)

\(=\left(2x^2-\dfrac{1}{2}\right)\left(-\dfrac{1}{2}x+3\right)\)

\(=-x^3+6x^2+\dfrac{1}{4}x-\dfrac{3}{2}\)

Answer 2

c, \(=\left(x^2-\dfrac{1}{4}\right)\left(4x-1\right)=4x^3-x^2-x+\dfrac{1}{4}\)

d, \(=\left(2x^2+x-x-\dfrac{1}{2}\right)\left(3-\dfrac{1}{2}x\right)=\left(2x^2-\dfrac{1}{2}\right)\left(3-\dfrac{1}{2}x\right)=6x^2-x^3-\dfrac{3}{2}+\dfrac{1}{4}x\)

Answer 3

\(\left(x-\dfrac{1}{2}\right).\left(x+\dfrac{1}{2}\right).\left(4x-1\right)\)

\(=\left(x^2-\dfrac{1}{4}\right).\left(4x-1\right)\)

\(=4x^3-x^2-x+\dfrac{1}{4}\)

\(\left(2x-1\right).\left(x+\dfrac{1}{2}\right).\left(3-\dfrac{1}{2}x\right)\)

\(=\left(2x^2-\dfrac{1}{2}\right).\left(3-\dfrac{1}{2}x\right)\)

\(=6x^2-x^3-\dfrac{3}{2}+\dfrac{1}{4}x\)