Question

Answer 1

a: \(A=\dfrac{x+2\sqrt{x}+1-x+2\sqrt{x}-1}{x-1}:\dfrac{\sqrt{x}-1+\sqrt{x}+1+2}{x-1}\)

\(=\dfrac{4\sqrt{x}}{x-1}\cdot\dfrac{x-1}{\sqrt{x}+2}=\dfrac{4\sqrt{x}}{\sqrt{x}+2}\)

b: \(A=\dfrac{1}{2}\) thì \(\dfrac{4\sqrt{x}}{\sqrt{x}+2}=\dfrac{1}{2}\)

\(\Leftrightarrow8\sqrt{x}=\sqrt{x}+2\)

\(\Rightarrow x=\dfrac{4}{49}\)