AB/AC=5/7
nên HB/HC=25/49
=>HB=25/49HC
\(AH^2=HB\cdot HC\)
\(\Leftrightarrow HC^2\cdot\dfrac{25}{49}=225\)
=>HC=21(cm)
\(HB=\dfrac{25}{49}\cdot21=\dfrac{75}{7}\left(cm\right)\)
BC=BH+CH=222/7(cm)
\(AB=\sqrt{HB\cdot BC}=\dfrac{15\sqrt{74}}{7}\left(cm\right)\)
\(AC=\sqrt{21\cdot\dfrac{222}{7}}=3\sqrt{74}\left(cm\right)\)