\(=\dfrac{\sqrt{3+\sqrt{5}}}{\sqrt{3-\sqrt{5}}}+\dfrac{\sqrt{3-\sqrt{5}}}{\sqrt{3+\sqrt{5}}}\\ =\dfrac{\sqrt{\left(3+\sqrt{5}\right)^2}+\sqrt{\left(3-\sqrt{5}\right)^2}}{\sqrt{\left(3-\sqrt{5}\right)\left(3+\sqrt{5}\right)}}\\ =\dfrac{3+\sqrt{5}+3-\sqrt{5}}{1}=3\)