Question

Answer 1

a: ĐKXĐ: x>=0

\(\sqrt{2x}< \dfrac{1}{3}\)

=>2x<1/9

=>x<1/18

Vậy: 0<=x<1/18

b: ĐKXĐ: x<=1/6

\(\sqrt{-3x+\dfrac{1}{2}}>=5\)

=>-3x+1/2>=25

=>-3x>=49,5

=>x<=-16,5

Answer 2

a) \(\sqrt{2x}< \dfrac{1}{3}\)                       ( x ≥ 0)

⇔ \(2x< \dfrac{1}{9}\)

⇔ x < \(\dfrac{1}{18}\)

b) \(\sqrt{-3x+\dfrac{1}{2}}\ge5\)

⇔ \(-3x+\dfrac{1}{2}\ge25\)

⇔ \(3x\le\dfrac{49}{2}\)

⇔ \(x\le\dfrac{49}{6}\)