Question

Answer 1

a) \(n_{NaOH}=0,05.0,2=0,01\left(mol\right)\)

PTHH: C_nH_2n+1COOH  + NaOH --> C_nH_2n+1COONa + H₂O

                   0,01<-----------0,01

=> \(M_{C_nH_{2n+1}COOH}=\dfrac{0,74}{0,01}=74\left(g/mol\right)\)

=> n = 2

=> CTPT: C₂H₅COOH

CTCT: \(CH_3-CH_2-COOH\)

b)

\(n_{C_2H_5COOH\left(pư\right)}=\dfrac{0,01.70}{100}=0,007\left(mol\right)\)

PTHH: C₂H₅COOH + C₂H₅OH --H⁺,t^o--> C₂H₅COOC₂H₅ + H₂O

                0,007--------------------------->0,007

=> \(m_{C_2H_5COOC_2H_5}=0,007.102=0,714\left(g\right)\)