ĐKXĐ: \(x\ge1\)
\(\sqrt{2x-1}-3+\sqrt{x-1}-2=0\)
\(\Leftrightarrow\dfrac{2\left(x-5\right)}{\sqrt{2x-1}+3}+\dfrac{x-5}{\sqrt{x-1}+2}=0\)
\(\Leftrightarrow\left(x-5\right)\left(\dfrac{2}{\sqrt{2x-1}+3}+\dfrac{1}{\sqrt{x-1}+2}\right)=0\)
\(\Leftrightarrow x-5=0\)
\(\Leftrightarrow x=5\)