1: Ta có: \(\sqrt{3+\sqrt{5}}-\sqrt{3-\sqrt{5}}\)
\(=\dfrac{\sqrt{6+2\sqrt{5}}-\sqrt{6-2\sqrt{5}}}{\sqrt{2}}\)
\(=\dfrac{\sqrt{5}+1-\sqrt{5}+1}{\sqrt{2}}=\sqrt{2}\)
2: Ta có: \(\sqrt{2+\sqrt{3}}-\sqrt{2-\sqrt{3}}\)
\(=\dfrac{\sqrt{4+2\sqrt{3}}-\sqrt{4-2\sqrt{3}}}{\sqrt{2}}\)
\(=\dfrac{\sqrt{3}+1-\sqrt{3}+1}{\sqrt{2}}\)
\(=\sqrt{2}\)