x⋮12;x⋮125;x⋮130⇒x∈BC(12;125;130)

Ta có:12=2^2.3

125=5^3

130=2.5.13

Nên BCNN(12;125;130)=2^2.3.5^3.13=19500

BC(12;125;130)=B(19500)={0;19500;39000;.....}

⇒x=0

a) 2134<2143                                                         b)30000+100=29000+200

c) 2357>3257-1000                                                 d) 80000+18999<99999

e)1999+1=2000-1                                                    g) 20000+9000+500+70+6>29575

h) 38489+1=38490                                                  k) 2000+100+3 >2000+13

Gọi là bộ lạc bạn nhé

11 * 2 = 22