Học tại trường Chưa có thông tin
Đến từ Hà Nội , Chưa có thông tin
Số lượng câu hỏi 37
Số lượng câu trả lời 4733
Điểm GP 123
Điểm SP 189

Người theo dõi (11)

Đang theo dõi (8)

Hà Đức Thọ
Cô Tuyết Ngọc
Đỗ Tuệ Lâm
Citii?

Câu trả lời:

\(a.\) \(A=\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+\dfrac{1}{6\cdot7}\)

\(A=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}\)

\(A=\dfrac{1}{2}-\dfrac{1}{7}\)

\(A=\dfrac{7}{14}-\dfrac{2}{14}\)

\(A=\dfrac{5}{14}\)

\(b.\) \(D=\dfrac{2}{3\cdot4}+\dfrac{2}{4\cdot5}+...+\dfrac{2}{2022\cdot2023}\)

\(D=\dfrac{2}{3}-\dfrac{2}{4}+\dfrac{2}{4}-\dfrac{2}{5}+...+\dfrac{2}{2022}-\dfrac{2}{2023}\)

\(D=\dfrac{2}{3}-\dfrac{2}{2023}\)

\(D=\dfrac{4046}{6069}-\dfrac{6}{6069}\)

\(D=\dfrac{4040}{6969}\)

\(c.\) \(E=\dfrac{1}{1\cdot4}+\dfrac{1}{4\cdot7}+...+\dfrac{1}{37\cdot40}\)

\(E=\dfrac{1}{1}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{37}-\dfrac{1}{40}\)

\(E=\dfrac{1}{4}-\dfrac{1}{40}\)

\(E=\dfrac{10}{40}-\dfrac{1}{40}\)

\(E=\dfrac{9}{40}\)

\(d.\) \(J=\dfrac{1\cdot2\cdot3+2\cdot4\cdot6+4\cdot8\cdot12+7\cdot14\cdot21}{1\cdot3\cdot5+2\cdot6\cdot10+4\cdot12\cdot20+7\cdot21\cdot35}+\dfrac{3}{5}\)

\(J=\dfrac{1\cdot2\cdot3+1\cdot2\cdot3\cdot2\cdot2\cdot2+1\cdot2\cdot3\cdot4\cdot4\cdot4+1\cdot2\cdot3\cdot7\cdot7\cdot7}{1\cdot3\cdot5+1\cdot2\cdot5\cdot2\cdot2\cdot2+1\cdot2\cdot5\cdot4\cdot4\cdot4+1\cdot2\cdot3\cdot7\cdot7\cdot7}+\dfrac{3}{5}\)

\(J=\dfrac{1\cdot2\cdot3\cdot\left(1+2^3+4^3+7^3\right)}{1\cdot3\cdot5\cdot\left(1+2^3+4^3+7^3\right)}+\dfrac{3}{5}\)

\(J=\dfrac{1\cdot2\cdot3}{1\cdot3\cdot5}\cdot1+\dfrac{3}{5}\)

\(J=\dfrac{6}{15}+\dfrac{3}{5}\)

\(J=\dfrac{2}{5}+\dfrac{3}{5}\)

\(J=\dfrac{5}{5}=1\)