Question

hiệu 2 lấp phương

x³-8

x³-8y³

làm hộ với

Answer 1

\(x^3-8=x^3-2^3=\left(x-2\right)\left(x^2+2x+4\right)\)

\(x^3-8y^3=x^3-\left(2y\right)^3=\left(x-2y\right)\left[x^2+x\left(2y\right)+\left(2y\right)^2\right]=\left(x-2y\right)\left(x^2+2xy+4y^2\right)\)

Sai thì chịu

Answer 2

Answer 3

\(x^3-8=x^3-2^3=\left(x-2\right)\left(x^2+2x+4\right)\)

\(x^3-8y^3=x^3-\left(2y\right)^3=\left(x-2y\right)\left(x^2+2xy+4y^2\right)\)

Answer 4

a) \(x^3-8 \)
\(=x^3-2^3\)
\(=\left(x-2\right)\left(x^2+2x+4\right)\)

b) \(x^3-8y^3 \)
\(=x^3-\left(2y\right)^3\)
\(=\left(x-2y\right)\left(x^2+2xy+4y^2\right)\)