ghpt \(\left\{{}\begin{matrix}x^2+2x=\dfrac{4y}{x}+\dfrac{3}{y^2}\\x^2-\dfrac{2y^2}{x^2}=\dfrac{4y}{x}-6y\end{matrix}\right.\)
giải hệ phương trình: \(\left\{{}\begin{matrix}\dfrac{x^2}{16}+\dfrac{y^2}{4}+\dfrac{xy}{x+2y}=1\\\sqrt{x^2+16}+\dfrac{5}{2}\sqrt{x+2y}=2x+\sqrt{x^2+7}\end{matrix}\right.\)
Giải hệ phương trình
a. \(\left\{{}\begin{matrix}\dfrac{1}{2}\left(x+2\right)\left(y+3\right)-\dfrac{1}{2}xy=50\\\dfrac{1}{2}xy-\dfrac{1}{2}\left(x-2\right)\left(y-2\right)=32\end{matrix}\right.\)
b. \(\left\{{}\begin{matrix}\dfrac{3x+5}{x+1}-\dfrac{2}{y+4}=4\\\dfrac{2x}{x+1}-\dfrac{5y+9}{y+4}=9\end{matrix}\right.\)
c. \(\left\{{}\begin{matrix}x^2+y^2-2x-2y-23=0\\x-3y-3=0\end{matrix}\right.\)
d.\(\left\{{}\begin{matrix}\left(x-y\right)^2-3x-3y=4\\2x+y=3\end{matrix}\right.\)
1, \(\left\{{}\begin{matrix}x^3+2y^2-4y+29=0\\x^2+x^2y^2-18y=0\end{matrix}\right.\)
2, \(\left\{{}\begin{matrix}x^3+2y^2-4y+10=0\\x^2+x^2y^2-16y+12=0\end{matrix}\right.\)
3, \(\left\{{}\begin{matrix}x,y>0\\x+y=7\\\dfrac{9}{x}+\dfrac{16}{y}=7\end{matrix}\right.\)
4, \(\left\{{}\begin{matrix}x,y>0\\x+y=4\\\dfrac{4}{x}+\dfrac{9}{y}\le4\end{matrix}\right.\)
5, \(\left\{{}\begin{matrix}x^3+y^2=\dfrac{211}{27}\\x^2+y^2+xy-3x-4y+4=0\end{matrix}\right.\)
6, \(\left\{{}\begin{matrix}x^4+81y^2=697\\x^2+9y^2+3xy-9x-36y+36=0\end{matrix}\right.\)
giải hệ sau bằng phương pháp thế
a)\(\left\{{}\begin{matrix}2x-y=4\\x+5y=3\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}-2x+3y=-1\\x+2y=3\end{matrix}\right.\)
giải hệ sau:
a)\(\left\{{}\begin{matrix}x+y=-1\\2x+y=1\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{1}{5}\\\dfrac{3}{x}+\dfrac{4}{y}=2\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}2\dfrac{5}{x-1}+\dfrac{3}{3y-2}=1\\\dfrac{2}{2x-1}+\dfrac{1}{3y-2}=1\end{matrix}\right.\)
Giai he phuong trinh:
a) \(\left\{{}\begin{matrix}5x+3y=31\\\sqrt{\dfrac{x+2}{y-3}}+\sqrt{\dfrac{y-3}{x+2}}=2\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\dfrac{x}{y}-\dfrac{x}{y+12}=1\\\dfrac{x}{y-12}-\dfrac{x}{y}=2\end{matrix}\right.\)
Tìm tất cả bộ ba số x,y,z thoả mãn:
\(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{2}{y}+\dfrac{3}{z}=1\\\dfrac{12}{yz}-\dfrac{1}{x^2}=1\end{matrix}\right.\)
Gỉai hệ phương trình sau đây :
\(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{1}{24}\\\dfrac{1}{x}-\dfrac{3}{2y}=0\end{matrix}\right.\)
Giải hệ phương trình
\(\left\{{}\begin{matrix}\dfrac{2x+2}{x+y}-\dfrac{3y}{x-y}=-5\\\dfrac{x+1}{x+y}+\dfrac{x}{x-y}=6\end{matrix}\right.\)