Ôn tập hệ hai phương trình bậc nhất hai ẩn
Các câu hỏi tương tự
giải hệ phương trình:
a)\(\left\{{}\begin{matrix}\dfrac{x+1}{x-1}+\dfrac{3y}{y+2}=7\\\dfrac{2}{x-1}-\dfrac{5}{y+2}=4\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}2\left(x^2-2x\right)+\sqrt{y+1}=0\\3\left(x^2-2x\right)-2\sqrt{y+1}=-7\end{matrix}\right.\)
Giải các hệ phương trình sau:a) \(\left\{{}\begin{matrix}\left(2x-y\right)^2-6x+3y=0\\x+2y=0\end{matrix}\right.\);b) \(\left\{{}\begin{matrix}\sqrt{\dfrac{2x-y}{x+y}}+\sqrt{\dfrac{x+y}{2x-y}}=2\\3x+y=14\end{matrix}\right.\)
giải hệ sau bằng phương pháp thế
a)left{{}begin{matrix}2x-y4x+5y3end{matrix}right.
b)left{{}begin{matrix}-2x+3y-1x+2y3end{matrix}right.
giải hệ sau:
a)left{{}begin{matrix}x+y-12x+y1end{matrix}right.
b)left{{}begin{matrix}dfrac{1}{x}+dfrac{1}{y}dfrac{1}{5}dfrac{3}{x}+dfrac{4}{y}2end{matrix}right.
c)left{{}begin{matrix}2dfrac{5}{x-1}+dfrac{3}{3y-2}1dfrac{2}{2x-1}+dfrac{1}{3y-2}1end{matrix}right.
Đọc tiếp
giải hệ sau bằng phương pháp thế
a)\(\left\{{}\begin{matrix}2x-y=4\\x+5y=3\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}-2x+3y=-1\\x+2y=3\end{matrix}\right.\)
giải hệ sau:
a)\(\left\{{}\begin{matrix}x+y=-1\\2x+y=1\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{1}{5}\\\dfrac{3}{x}+\dfrac{4}{y}=2\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}2\dfrac{5}{x-1}+\dfrac{3}{3y-2}=1\\\dfrac{2}{2x-1}+\dfrac{1}{3y-2}=1\end{matrix}\right.\)
Giải hệ phương trình
a. left{{}begin{matrix}dfrac{1}{2}left(x+2right)left(y+3right)-dfrac{1}{2}xy50dfrac{1}{2}xy-dfrac{1}{2}left(x-2right)left(y-2right)32end{matrix}right.
b. left{{}begin{matrix}dfrac{3x+5}{x+1}-dfrac{2}{y+4}4dfrac{2x}{x+1}-dfrac{5y+9}{y+4}9end{matrix}right.
c. left{{}begin{matrix}x^2+y^2-2x-2y-230x-3y-30end{matrix}right.
d.left{{}begin{matrix}left(x-yright)^2-3x-3y42x+y3end{matrix}right.
Đọc tiếp
Giải hệ phương trình
a. \(\left\{{}\begin{matrix}\dfrac{1}{2}\left(x+2\right)\left(y+3\right)-\dfrac{1}{2}xy=50\\\dfrac{1}{2}xy-\dfrac{1}{2}\left(x-2\right)\left(y-2\right)=32\end{matrix}\right.\)
b. \(\left\{{}\begin{matrix}\dfrac{3x+5}{x+1}-\dfrac{2}{y+4}=4\\\dfrac{2x}{x+1}-\dfrac{5y+9}{y+4}=9\end{matrix}\right.\)
c. \(\left\{{}\begin{matrix}x^2+y^2-2x-2y-23=0\\x-3y-3=0\end{matrix}\right.\)
d.\(\left\{{}\begin{matrix}\left(x-y\right)^2-3x-3y=4\\2x+y=3\end{matrix}\right.\)
Giải các hệ phương trình sau:
a) \( \left\{{}\begin{matrix}x\sqrt{5}-\left(1+\sqrt{3}\right)y=1\\\left(1-\sqrt{3}\right)x+y\sqrt{5}=1\end{matrix}\right.;\)
b) \(\left\{{}\begin{matrix}\dfrac{2x}{x+1}+\dfrac{y}{y+1}=\sqrt{2}\\\dfrac{x}{x+1}+\dfrac{3y}{y+1}=-1\end{matrix}\right..\)
1, left{{}begin{matrix}x^3+2y^2-4y+290x^2+x^2y^2-18y0end{matrix}right.
2, left{{}begin{matrix}x^3+2y^2-4y+100x^2+x^2y^2-16y+120end{matrix}right.
3, left{{}begin{matrix}x,y0x+y7dfrac{9}{x}+dfrac{16}{y}7end{matrix}right.
4, left{{}begin{matrix}x,y0x+y4dfrac{4}{x}+dfrac{9}{y}le4end{matrix}right.
5, left{{}begin{matrix}x^3+y^2dfrac{211}{27}x^2+y^2+xy-3x-4y+40end{matrix}right.
6, left{{}begin{matrix}x^4+81y^2697x^2+9y^2+3xy-9x-36y+360end{matrix}right.
Đọc tiếp
1, \(\left\{{}\begin{matrix}x^3+2y^2-4y+29=0\\x^2+x^2y^2-18y=0\end{matrix}\right.\)
2, \(\left\{{}\begin{matrix}x^3+2y^2-4y+10=0\\x^2+x^2y^2-16y+12=0\end{matrix}\right.\)
3, \(\left\{{}\begin{matrix}x,y>0\\x+y=7\\\dfrac{9}{x}+\dfrac{16}{y}=7\end{matrix}\right.\)
4, \(\left\{{}\begin{matrix}x,y>0\\x+y=4\\\dfrac{4}{x}+\dfrac{9}{y}\le4\end{matrix}\right.\)
5, \(\left\{{}\begin{matrix}x^3+y^2=\dfrac{211}{27}\\x^2+y^2+xy-3x-4y+4=0\end{matrix}\right.\)
6, \(\left\{{}\begin{matrix}x^4+81y^2=697\\x^2+9y^2+3xy-9x-36y+36=0\end{matrix}\right.\)
giải hpt:
1, \(\left\{{}\begin{matrix}x^2y^2+4=2y^2\\\left(xy+2\right)\left(y-x\right)=x^3y^3\end{matrix}\right.\)
2, \(\left\{{}\begin{matrix}x^2+y^2-4xy\left(\dfrac{2}{x-y}-1\right)=4\left(4+xy\right)\\\sqrt{x-y}+3\sqrt{2y^2-y+1}=2y^2-x+3\end{matrix}\right.\)
Tìm tất cả bộ ba số x,y,z thoả mãn:
\(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{2}{y}+\dfrac{3}{z}=1\\\dfrac{12}{yz}-\dfrac{1}{x^2}=1\end{matrix}\right.\)
Giải các hệ phương trình :
a) \(\left\{{}\begin{matrix}\left(x+3\right)\left(y+5\right)=\left(x+1\right)\left(y+8\right)\\\left(2x-3\right)\left(5y+7\right)=2\left(5x-6\right)\left(y+1\right)\end{matrix}\right.\);
b) \(\left\{{}\begin{matrix}\dfrac{2x-3}{2y-5}=\dfrac{3x+1}{3y-4}\\2\left(x-3\right)-3\left(y+2\right)=-16\end{matrix}\right.\).