Question

x(4x2-1)=0

Answer 1

\(x\left(4x^2-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\4x^2-1=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\frac{1}{2}\\x=\frac{1}{2}\end{matrix}\right.\)

Answer 2

cho mk hỏi là 4 nhân 2 hay 4x nhân 2

Answer 3

\(x\left(4x^2-1\right)=0\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\4x^2-1=0\end{matrix}\right.\)\(\left[{}\begin{matrix}x=0\\4x^2=1\\x^2=\frac{1}{4}\\x=\frac{1}{2}hoac\frac{-1}{2}\end{matrix}\right.\)

Vậy \(x\in\left\{0;\frac{1}{2};\frac{-1}{2}\right\}\)

Answer 4

\(x\left(4x^2-1\right)=0\)

=> \(\left[{}\begin{matrix}x=0\\4x^2-1=0\end{matrix}\right.\) => \(\left[{}\begin{matrix}x=0\\4x^2=0+1=1\end{matrix}\right.\) => \(\left[{}\begin{matrix}x=0\\x^2=1:4\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}x=0\\x^2=\frac{1}{4}\end{matrix}\right.\) => \(\left[{}\begin{matrix}x=0\\x=\frac{1}{2}\\x=-\frac{1}{2}\end{matrix}\right.\)

Vậy \(x\in\left\{0;\frac{1}{2};-\frac{1}{2}\right\}.\)

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