\(x^2\) - x - 12
=\(x^2\) - 4x +3x -12
=(\(x^2-4x\)) + (3x - 12)
=x(x-4) + 3(x-4)
=(x+3) (x-4)
\(x^2\)
Đúng 0
Bình luận (1)
\(x^2-x-12=x^2+3x-4x-12\)
\(=\left(x^2+3x\right)-\left(4x+12\right)\)
\(=x\left(x+3\right)-4\left(x+3\right)\)
\(=\left(x-4\right)\left(x+3\right)\)
Đúng 0
Bình luận (0)
