\(\left(x-5\right)\left(x+3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-5=0\\x+3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=-3\end{matrix}\right.\)
Vậy \(x\in\left\{5;-3\right\}\)
Ôn tập chương II
Các câu hỏi tương tự
Giải giúp em, Xin cảm ơn
a | 2x - 3 | - | 5 | = | -11 | - 3
b | x | + | y | = 0
c) | x - 3 | + | y + 2 | = 0
d) x.(x + 7) = 0
e) (x + 12).(x-3) = 0
f) (-x + 5).(3 – x ) = 0
g) x.(2 + x).( 7 – x) = 0
h) (x - 1).(x +2).(-x -3) = 0
a) x ( x + 0 ) = 0
b) ( x - 1 ) ( 7 - x ) = 0
c) ( -x + 5 ) ( 3 - x ) = 0
d) ( x + 5 ) + ( x - 9 ) = 13
e) ( 4 + x ) + ( x - 7 ) = x + 2
f) ( 3x + 5 ) - ( 2x - 7) = 4 - x
g) ( x - 1 )2 = 36
h) ( 3 - x ) 3 = -27
Bài 3. Tìm x biết:
a) (x+4) - (3×-2)= 5
b) 10(x-7)=8(x-4)+x
c) 19 - 5(x-1) = 4x + 6
d) 5(x-7)+3(x+2)=7(x-5)+2. |-4| . (-3).5.(-1)2020
e) (x-7)(-3x+9)=0
g) (x2 -4)(|x+10|-18)=0
i) (x-2)2-25=0
k) (x3+64)(-4 - 10x) = 0
Tìm x : a) (x+3) = 0
b) (x-2) (5-x)=0
(x+1)+(x+3)+(x+5)+....+(x+99)=0
X-7 = -5 (x+2) = 0 (3x - 24) . 73 =2.74 | x - 5 | = |-7| x- [42 + ( -28) = -8 ( 7x - x ) - ( 25+7 ) = -25 |x-3| = |5| + | -7 | ( x : 3-4 ) : 5 =15 | x -3 | = 7 - (-2) 128 -3 . (x+4) = 23 4 - ( 7-x ) = x - (13-4 ) BÀI 2 : TÍNH NHANH S1 = 1+2+3+.......999 S1= 10 +12 + 14 +.......2010 S3 + 21 + 23 + 25 + .......10001
Tìm số nguyên x biết :
1) 10+3.(x-1)=10+6x
2) 2.(x-2)+3.(3-x)=-4
3) (|x-2|+1).(x-3)=0
4) (x+5).(-3x-15)=0
2. Tìm số nguyên x, biết:
a) x+5+2.x=17
b) x-11=2.x+4
c) (3-x).(x+5)=0
d) (2.x+2).(x-19)=0
e) (x+2)3=(-125)
f) |x-3|=4
g) 2.|7-x|=16
h) 12-2.|x-10|=(-18)
Tìm x biết:
a) 5.(x-7) = 0
b) 34.(2.x - 6 ) = 0
c) 25 + (15-x) = 30
d) 43 -(24-x) = 20
e) 2. (x - 5) -17 =25
f) 24 + 3.(5 - x) = 27
g) 15 : x – 2 = 3
h) (32 – x : 5): 13 = 2
g) (6 – 2x)(x – 8) =0
Mg bt câu nào thỳ giúp mk câu đó nhé