\(\dfrac{x-1}{9}=\dfrac{8}{3}\\ \Rightarrow\left(x-1\right).3=8.9\\ \Rightarrow3x-3=72\\ \Rightarrow3x=75\\ \Rightarrow x=25\)
Vậy \(x=25\)
Ta có: \(\dfrac{x-1}{9}=\dfrac{8}{3}\)
\(\Leftrightarrow x-1=\dfrac{8\cdot9}{3}=8\cdot3=24\)
hay x=25
Vậy: x=25