a, \(9^3.27^4=\left(3^2\right)^3.\left(3^3\right)^4=3^6.3^{12}=3^{6+12}=3^{18}\)
b, \(27^3.9^3.243=\left(3^3\right)^3.\left(3^2\right)^3.3^5=3^9.3^6.3^5=3^{9+6+4}=3^{19}\)
\(c,4^3.8^2=\left(2^2\right)^3.\left(2^3\right)^2=2^6.2^6=2^{6+6}=2^{12}\)
Chúc bạn học tốt !