Bài 1: Nhân đơn thức với đa thức
Các câu hỏi tương tự
Tính giá trị biểu thức:
\(N=3.\dfrac{1}{117}.\dfrac{1}{119}-\dfrac{4}{117}.5\dfrac{118}{119}-\dfrac{5}{117.119}+\dfrac{8}{39}\)
Tính giá trị biểu thức
\(A=3\dfrac{1}{117}.\dfrac{1}{119}-\dfrac{4}{117}.5\dfrac{118}{119}-\dfrac{5}{117.119}+\dfrac{8}{39}\)
help me ~~
a, 5*(4x-1)+2*(1-3x)-6*(x+5)=10
b, 2x*(x+1)+3*(x-1)*(x+1)-5x*(x+1)+6x mũ 2 = 0
c, 4*(x-1)*(x+5)-(x+2)*(x+5)-3(x-1)*(x+2)=0
d,2*(5x-8)-3*(4x-5)=4*(3x-4)+11
tìm x
a.\(\frac{3}{5}-\frac{x}{4}=\frac{7}{2}\)
b,\(\frac{x-5}{4}-\frac{3}{5}=\frac{1}{2}\)
c,\(1-\frac{8}{x}=\frac{-3}{5}\)
d,\(\frac{4}{3}=\frac{8-x}{2x+3}\)
Tìm x:
1/ 4.(18-5x)-12.(3x-7)=15.(2x-16)-6.(x+14) 2/5.(3x+5)-4(2x-3)=5x+3.(2x+12)+1 3/2.(5x-8)-3(4x-5)=4(3x-4)+11 4/5x-3.{4x-2.[4x-3(5x-2)]}=182tìm x,
a, \(2(x-3)-5\times(2x-4)=0\)
b,\(3+\frac{1}{x-8}=0\)
c,\(\frac{8}{3}-\frac{2x+3}{5}=-\frac{-7}{3}\)
d,\(\frac{1}{9}=\frac{5}{3x-5}=0\)
Rút gọn biểu thức
a,(8-5x)(x-2)+4(x-2)(x+1)+2(x-2)(x+2)+10
b,4(x-1)(x+5)-(x+2)(x+5)-3(x-1)(x+2)
Tìm x, biết:
a, (x+8).(x+6)-x^2=104
b, (x+1).(x+2)-(x-3).(x+4)=6
c, 3.(2x-1).(x+2)-2.(3x+2).(x-4)=5
16 Tìm x, biết
a) 4(x+2)-7(2x-1)+9(3x-4)=30 ; b) 2(5x-8)-3(4x-5)=4(3x-4)+11
c) 5x(1-2x)-10(x+8)=0 ; d) (5x-3).4x-2x.(10x-3)=15