Question

Tính giá trị các biểu thức:

\(4\frac{7}{9}:\left(\frac{-5}{18}\right)+\frac{48}{9}.\left(-3\frac{3}{5}\right)\)

Answer 1

Tính giá trị của biểu thức:

4\(\dfrac{7}{9}\):\(\left(\dfrac{-5}{18}\right)\)+\(\dfrac{48}{9}\).(-3\(\dfrac{3}{5}\))

=\(\dfrac{43}{9}\).\(\dfrac{-18}{5}\)+\(\dfrac{48}{9}\).\(\dfrac{-12}{5}\)

=\(\dfrac{43.\left(-18\right)}{9.5}\)+\(\dfrac{48.\left(-12\right)}{9.5}\)

=\(\dfrac{43.\left(-2\right)}{1.5}\)+\(\dfrac{48.\left(-4\right)}{3.5}\)

=\(\dfrac{-86}{5}\)+\(\dfrac{-192}{15}\)

=\(\dfrac{-258}{15}\)+\(\dfrac{-192}{15}\)

=-30

Answer 2

\(4\dfrac{7}{9}:\left(\dfrac{-5}{18}\right)+\dfrac{48}{9}.\left(-3\dfrac{3}{5}\right)\)

\(\dfrac{43}{9}:\left(\dfrac{-5}{18}\right)+\dfrac{48}{9}.\left(\dfrac{-18}{5}\right)=\dfrac{43}{9}.\left(\dfrac{-18}{5}\right)+\dfrac{48}{9}.\left(\dfrac{-18}{5}\right)=\dfrac{-18}{5}.\left(\dfrac{43}{9}+\dfrac{48}{9}\right)=\dfrac{-18}{5}.9=\dfrac{-162}{5}\)