\(=\left(1\frac{1}{2}+\frac{1}{2}\right)+\left(2\frac{2}{3}+\frac{1}{3}\right)+...+\left(50\frac{50}{51}+\frac{1}{51}\right)\)
\(=2+3+...+51\)
\(=\frac{\left(2+51\right)50}{2}\)
\(=1325\)
\(=\left(1\frac{1}{2}+\frac{1}{2}\right)+\left(2\frac{2}{3}+\frac{1}{3}\right)+...+\left(50\frac{50}{51}+\frac{1}{51}\right)\)
\(=2+3+...+51\)
\(=\frac{\left(2+51\right)50}{2}\)
\(=1325\)
Câu 8:=
Tính \(1\frac{1}{2}+2\frac{2}{3}+3\frac{3}{4}+4\frac{4}{5}+...+50\frac{50}{51}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{51}\)
bài 1: tính A:=\(\frac{1}{2}-\frac{2}{3}+\frac{3}{4}-\frac{4}{5}+\frac{5}{6}-\frac{6}{7}-\frac{5}{6}+\frac{4}{5}-\frac{3}{4}+\frac{2}{3}-\frac{2}{3}-\frac{1}{2}\)
Bài 2: Cho B=\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+.....+\frac{1}{49}-\frac{1}{50}\)
Chứng minh rằng: \(\frac{7}{12}< A< \frac{5}{6}\)
Tính bằng cách hợp lí
a)\(\frac{1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}}{1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}}:\frac{13+\frac{13}{2}+\frac{13}{3}+\frac{13}{4}}{17-\frac{17}{2}+\frac{17}{3}-\frac{17}{4}}\)
b)\(\frac{0,125-\frac{1}{5}+\frac{1}{7}}{0,375-\frac{3}{5}+\frac{3}{7}}+\frac{\frac{1}{2}+\frac{1}{3}-0,2}{\frac{3}{4}+0,5-\frac{3}{10}}\)
Tính C
\(C=\frac{1}{7}+\frac{1}{7^2}+\frac{1}{7^3}+\frac{1}{7^4}+.....+\frac{1}{7^{50}}+\frac{1}{6.7^{50}}\)
1) So Sánh A và B biết :
A = \(\frac{10^{50}+1}{10^{51}+1}\) ; B = \(\frac{10^{51}+1}{10^{52}+1}\)
2) Tìm x biết :
\(\frac{x-1}{99}+\frac{x-2}{98}+\frac{x-3}{97}-4=0\)
3) Tính giá trị của biểu thức
\(\frac{1}{1.2} +\frac{1}{2.3}+\frac{1}{3.4}+......+\frac{1}{1999.2000}\)
MỌI NGƯỜI LÀM ĐI NHÉ ! CHÚC MỌI NGƯỜI VUI VẺ !
cho A= \(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2^{100}-1}\) chứng minh A>50
\(a.A=[\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}]+\frac{1890}{2005}+115\)
b.B=\(\left[\frac{1\frac{11}{31}\cdot4\frac{3}{7}-\left(15-6\cdot\frac{1}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(42-5\frac{1}{3}\right)}\cdot\left(-1\frac{19}{93}\right)\right]\cdot\frac{31}{50}\)
B. Tự luận
I: Đại số:
Bài 1: Thực hiện phép tính
1) 11/24 - 5/41 + 13/24 + 0,5 - 36/41
2) -12 : (3/4 - 5/6)^2
3) 7/23. [(-8/6) - 45/18]
4) \(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
5) (\(1+\frac{2}{3}-\frac{1}{4}\) ) (\(0,8\:-\frac{3}{4}\) )^2
6) 16\(\frac{2}{7}:\left(\frac{-3}{5}\right)+28\frac{2}{7}:\frac{3}{5}\)
7) \((2^2:\frac{4}{3}-\frac{1}{2}\) ) . 6/5 - 17
8) (1/3)^50 .(-9)^25 -2/3:4
9) 3/5: ( -1/15 - 1/6 )+3/5:( -1/3 - 1\(\frac{1}{15}\) )
10) (-6,5).5,7+5,7.(-3,5)
11) 10.√0,01.√16/9+3√49-1/6√4
12) \(\frac{2⁴.2⁶}{\left(2⁵\right)^2}-\frac{2⁵.15^3}{6^3.10^2}\)
Bài 2. Tìm x, biết
1) x/12 - 5/6 = 1/12
2) 2/3 - 1\(\frac{4}{15}x=\frac{-3}{5}\)
3) -2^3 + 0,5x =1,5
Nhiêu đó thôi mik còn thiếu nhiều lắm