Question

Tìm x:

\(\left(2x-3\right)\left(\frac{3}{4}x+1\right)=0\)

Answer 1

\(\Rightarrow\left[\begin{array}{nghiempt}2x-3=0\\\frac{3}{4}.x+1=0\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}2x=3\\\frac{3}{4}.x=-1\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{3}{2}\\x=-\frac{4}{3}\end{array}\right.\)

Vậy x = 3 /2 ; x = - 4 / 3

Answer 2

\(\left(2x-3\right)\left(\frac{3}{4}x+1\right)=0\)

\(\Rightarrow\begin{cases}2x-3=0\\\frac{3}{4}x+1=0\end{cases}\)

\(\Rightarrow\begin{cases}2x=0+3\\\frac{3}{4}x=0-1\end{cases}\)

\(\Rightarrow\begin{cases}2x=3\\\frac{3}{4}x=-1\end{cases}\)

Answer 3

(2x-3) (3/4x+1)=0

=)2x-3=0 hoặc 3/4x+1=0

=)2x=3 hoặc 3/4x=-1

=)x=3/2 hoặc x=-4/3

Answer 4

\(\left(2x-3\right)\left(\frac{3}{4}x+1\right)=0\)

\(\Rightarrow2x-3=0\) hoặc \(\frac{3}{4}x+1=0\)

+) \(2x-3=0\Rightarrow x=\frac{3}{2}\)

+) \(\frac{3}{4}x+1=0\Rightarrow x=\frac{-4}{3}\)

Vậy \(x=\frac{3}{2}\) hoặc \(x=\frac{-4}{3}\)