\(\Leftrightarrow2x-\dfrac{5}{4}=\dfrac{5}{2}\left(x-\dfrac{1}{3}\right)\)
\(\Leftrightarrow2x-\dfrac{5}{2}x=-\dfrac{5}{6}+\dfrac{5}{4}\)
\(\Leftrightarrow x\cdot\dfrac{-1}{2}=\dfrac{5}{12}\)
hay \(x=-\dfrac{5}{6}\)
\(\Leftrightarrow2x-\dfrac{5}{4}=\dfrac{5}{2}\left(x-\dfrac{1}{3}\right)\)
\(\Leftrightarrow2x-\dfrac{5}{2}x=-\dfrac{5}{6}+\dfrac{5}{4}\)
\(\Leftrightarrow x\cdot\dfrac{-1}{2}=\dfrac{5}{12}\)
hay \(x=-\dfrac{5}{6}\)
Giúp mk vs đg cần gấp nha cảm ơn mấy bạn nhiều lắm !!!
\(\left(\frac{1}{2}\right)^5.x=\left(\frac{1}{2}\right)^7\)
\(\left(\frac{3}{7}\right)^2.x=\left(\frac{9}{21}\right)^2\)
Bài tìm x biết :
2x=2
3x=34
7x=77
(-3)x=(-3)5
(-5)x=(-5)4
2x=4
2x=8
2x=16
3x+1=32
5x-1=5
6x+4=610
52x-7=511
(-2)4x+2=64
\(\left(\frac{1}{2}\right)^x=\left(\frac{1}{2}\right)^5\)
\(\left(\frac{5}{6}\right)^{2x}=\left(\frac{5}{6}\right)^5\)
\(\left(\frac{3}{4}\right)^{2x-1}=\left(\frac{3}{4}\right)^{5x-4}\)
\(\left(-\frac{1}{10}\right)^x=\frac{1}{100}\)
\(\left(-\frac{3}{2}\right)^x=\frac{9}{4}\)
\(\left(-\frac{3}{5}\right)^{2x}=\frac{9}{25}\)
\(\left(-\frac{2}{3}\right)^x=-\frac{8}{27}\)
Tìm x: \(\left|x-5\right|+\frac{\left(x-1\right)\left(x-3\right)}{2}=\frac{\left(x+1\right)^2}{3}-\frac{\left(1-2x\right)^2}{4}\)
1. Tìm x ϵ Q sao cho:
a) (2x-3). (x+1) < 0.
b) \(\left(x-\frac{1}{2}\right).\left(x+3\right)\)> 0.
2. Tính:
S=\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{999.1001}\)
3. Tìm x: Biết x không thuộc{-2; -5; -10; -17}
\(\frac{3}{\left(x+2\right).\left(x+5\right)}+\frac{5}{\left(x+5\right).\left(x+10\right)}+\frac{7}{\left(x+10\right).\left(x+17\right)}=\frac{x}{\left(x+2\right).\left(x+17\right)}\)
Tìm x : \(\frac{\left(x-3\right)^2}{2}-1\frac{1}{3}\left(x+2\right)^2-\frac{5}{4}\left(x-1\right)\left(x+1\right)=1\frac{1}{2}x\left(x-2\right)-x-4\)
\(\frac{5}{3}\left(3x-3\right)+\frac{1}{2}=\frac{1}{2}\left(2x-1\right)\) \(\frac{-4}{3}\left(x-\frac{1}{4}\right)=\frac{3}{2}\left(2x-1\right)\) ai giup minh voi nhanh nhanh
Tìm x biết:
a) \(\left(x+\frac{1}{2}\right).\left(x-\frac{3}{4}\right)=0\)
b) \(\left(\frac{1}{2}x-3\right).\left(\frac{2}{3}x+\frac{1}{2}\right)=0\)
c) \(\frac{2}{3}-\frac{1}{3}.\left(x-\frac{3}{2}\right)-\frac{1}{2}\left(2x+1\right)=5\)
d) \(4x-\left(x+\frac{1}{2}\right)=2x-\left(\frac{1}{2}-5\right)\)
MONG CÁC BN GIÚP ĐỠ MK BÀI NÀY , MK ĐANG CẦN RẤT GẤP GIẢI CHI TIẾT RA GIÚP MK VS NHÉ!!!!MK RẤT CẢM ƠN
Tìm x : \(\frac{\left(x-3\right)^2}{2}-1\frac{1}{3}\left(x+2\right)^2-\frac{5}{4}\left(x-1\right)\left(x+1\right)=1\frac{1}{2}x\left(x-2\right)-x-4\)
\(2x-\frac{5}{4}=\left(3-\frac{1}{2}\right).\left(x-\frac{1}{3}\right)\) Tìm x
Các bn ơi giúp mk với
Tìm x:
a)\(3x-\left|2x+1\right|=2\)
b)\(\left|3x-5\right|+\left|2x+3\right|=7\)
c)\(\left|x-\frac{1}{3}\right|+\frac{4}{5}=\left|\left(-3,2\right)+\frac{2}{5}\right|\)
Các bn làm đc câu nào thì làm nha . Help me