a) \(\left(x-4\right)^3=8\)
\(\Leftrightarrow x-4=2\Leftrightarrow x=6\)
b) \(\frac{x}{2}=\frac{6}{10}\)
\(\Leftrightarrow x=\frac{2\cdot6}{10}=\frac{12}{10}=1,2\)
a) (x - 4)3 = 8
=> (x - 4)3 = 23
=> x - 4 = 2
=> x = 2 + 4 = 6
Vậy x = 6
b) \(\frac{x}{2}=\frac{6}{10}\)
=> \(\frac{x}{2}=\frac{3}{5}\)
=> 5.x = 2.3 = 6
=> \(x=\frac{6}{5}\)
Vậy \(x=\frac{6}{5}\)
\(\left(x-4\right)^3=8\)
\(\left(x-4\right)^3=2^3\)
\(\Rightarrow x-4=2\)
\(\Rightarrow x=2+4\)
\(\Rightarrow x=6\)
\(\frac{x}{2}=\frac{6}{10}\Rightarrow\frac{x}{2}=\frac{3}{5}\Rightarrow x=\frac{3.2}{5}=\frac{6}{5}=1,2\)
a, ( x-4)3 = 8
Ta có: 8= 23
=> ( x- 4) 3= 23
=> x- 4= 2
=> x= 2+ 4
=> x= 6
b, \(\frac{x}{2}=\frac{6}{10}\)
=> x= \(\frac{6}{10}.2=\frac{12}{10}=\frac{6}{5}\)
Vậy x= 6/5
a) \(\left(x-4\right)^3=8\)
\(\Rightarrow\left(x-4\right)^3=2^3\)
\(\Rightarrow x-4=2\)
\(\Rightarrow x=6\)
Vậy \(x=6\)
b) \(\frac{x}{2}=\frac{6}{10}\)
\(\Rightarrow10x=2.6\)
\(\Rightarrow10x=12\)
\(\Rightarrow x=\frac{12}{10}=\frac{6}{5}\)
Vậy \(x=\frac{6}{5}\)