Question

Tìm x?

Answer 1

Xét tứ giác PSQR có :

^P + ^Q + ^S + ^R = 360^o

Mà ^S = 65^o ; ^R = 95^o

=> ^P + ^Q = 360^o - 65^o - 95^o

=> ^P + ^Q = 200^o

=> x + x = 200^o

=> 2x = 200^o

=> x = 100^o

Vậy x = 100^o

Answer 2

xét tứ giác PSRQ,có:

\(\widehat{P}+\widehat{S}+\widehat{R}+\widehat{Q}=360^o\)

Mà \(\widehat{R}=95^o\) ; \(\widehat{S}=65^o\) ; \(\widehat{Q}=\widehat{P}=x\) nên:

\(95^o+65^o+x+x=360^o\)

\(\Rightarrow160^o+2x=360^o\)

\(\Rightarrow2x=200^o\)

\(\Rightarrow x=100^o\)