ĐKXĐ: \(x\ge1\)
\(\left(\sqrt{3x}-\sqrt{2x+3}\right)+\left(\sqrt{2x-2}-\sqrt{x+1}\right)=0\)
\(\Leftrightarrow\dfrac{x-3}{\sqrt{3x}+\sqrt{2x+3}}+\dfrac{x-3}{\sqrt{2x-2}+\sqrt{x+1}}=0\)
\(\Leftrightarrow\left(x-3\right)\left(\dfrac{1}{\sqrt{3x}+\sqrt{2x+3}}+\dfrac{1}{\sqrt{2x-2}+\sqrt{x+1}}\right)=0\)
\(\Leftrightarrow x-3=0\)
\(\Leftrightarrow x=3\)