Áp dụng tính chất dãy tỉ số bằng nhau, ta có
\(\dfrac{x-1}{2}=\dfrac{y-3}{4}=\dfrac{z-2}{3}=\dfrac{3y-9}{12}=\dfrac{4z-8}{12}\)
\(=\dfrac{x-1-3y+9+4z-8}{2-12+12}=\dfrac{\left(x-3y+4z\right)+9-8-1}{2}=4\)
Ta có
\(\dfrac{x-1}{2}=4\Rightarrow x-1=8\Rightarrow x=9\)
\(\dfrac{y-3}{4}=4\Rightarrow y-3=16\Rightarrow y=19\)
\(\dfrac{z-2}{3}=4\Rightarrow z-2=12\Rightarrow z=14\)