x =\(\left[{}\begin{matrix}\dfrac{5}{3}\\-\dfrac{5}{3}\end{matrix}\right.\)
\(\left|x\right|-1=\dfrac{3}{2}\Rightarrow\left|x\right|=\dfrac{5}{2}\)
\(\Rightarrow x=\pm\dfrac{5}{2}\)
⇒x=3/2+1=5/2 hoặc x=-3/2+1=-1/2
Vậy x=5/2 hoặc x=-1/2
x =\(\left[{}\begin{matrix}\dfrac{5}{3}\\-\dfrac{5}{3}\end{matrix}\right.\)
\(\left|x\right|-1=\dfrac{3}{2}\Rightarrow\left|x\right|=\dfrac{5}{2}\)
\(\Rightarrow x=\pm\dfrac{5}{2}\)
⇒x=3/2+1=5/2 hoặc x=-3/2+1=-1/2
Vậy x=5/2 hoặc x=-1/2
Tìm \(x\)\(\in\)\(Q\):
\(a\)\()\) \(|0,5.x-2|-|x+\dfrac{2}{3}|=0\)
\(b)\) \(2x-|x+1|=\dfrac{-1}{2}\)
Tìm x: | 2x + 3/4|= 1/2
\(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
tìm GTLN của biểu thức :
a. A=10-|x-2|
b. B=-3\(\times x^2+2014\)
c. C=\(\dfrac{x^2+5}{x^2+1}\)
d. D=\(\dfrac{1}{\left|x-2\right|+3}\)
e. E=\(\dfrac{1}{\sqrt{x}+3}\)
Tìm x, biết:
a) \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b) \(2\left|x+3\frac{1}{2}\right|+\left|x\right|-3\frac{1}{2}=\left|2\frac{1}{5}-x\right|\)
1/Tìm x,biết:
a/|2x-5|=4
b/1/3-|5/4-2x|=1/4
c/2×|2x-3|=1/2
1. Tìm x:
c) 2- \(\frac{1}{3}\) / x-1/ = 5
e) /\(\frac{3}{5}\)/= /x-1/ = /\(\frac{-2}{5}\)/
(Mơn trc)
Bài 4: Tính hợp lý
a) \(A=\left(\left|\frac{-3}{4}\right|+\left|\frac{-2}{5}\right|\right):\frac{3}{7}+\left(\frac{-3}{5}+\left|\frac{-1}{4}\right|\right):\frac{3}{7}\)
b) \(B=2\frac{5}{23}-\left(\frac{-7}{9}\right)-\left|\frac{-5}{23}\right|+\frac{12}{9}+\left|-0,75\right|\)
Bài 5 : Tìm x :
\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\left|\frac{-2}{3}\right|\)
b) \(\left|x\right|:\left(\frac{1}{9}-\frac{2}{5}\right)=\frac{-1}{2}\)
c) \(\left(x-\frac{1}{5}\right).\left(1\frac{3}{5}+2x\right)=0\)
Tìm x , y , z ∈ Q : a) x + y = \(\frac{1}{2}\) ; b) y + 2 = \(\frac{1}{3}\) ; c) x+2= \(\frac{1}{4}\)