Ta có:
\(1+\sqrt{1+\sqrt{x-16}}=4\)
\(\Rightarrow\sqrt{1+\sqrt{x-16}}=3\)
\(\Rightarrow\left(\sqrt{1+\sqrt{x-16}}\right)^2=3^2\)
\(\Rightarrow1+\sqrt{x-16}=9\)
\(\Rightarrow\)\(\sqrt{x-16}=8\)
\(\Rightarrow\left(\sqrt{x-16}\right)^2=8^2\)
\(\Rightarrow x-16=64\)
\(\Rightarrow x=80\)
Vậy x=80
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