Ta có : \(\left(x+5\right)\left(x+6\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+5=0\\x+6=0\end{array}\right.\Leftrightarrow\left[\begin{array}{nghiempt}x=0-5\\x=0-6\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-5\\x=-6\end{array}\right.\)
Vậy \(x\in\left\{-5;-6\right\}\)
Để \(\left(x+5\right)\left(x+6\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+5=0\\x+6=0\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0-5\\x=0-6\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=-5\\x=-6\end{array}\right.\)
\(\Rightarrow x\in\left\{-6;-5\right\}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+5=0\\x+6=0\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=-5\\x=-6\end{array}\right.\)
Vậy x= - 5 ; x = - 6
\(\left(x+5\right)\left(x+6\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0-5\\x=0-6\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=-5\\x=-6\end{array}\right.\)
Vậy x thuộc {-5;-6}
Ta có : ( x + 5 ) ( x + 6 )
\(\Rightarrow\begin{cases}x+5=0\\x+6=0\end{cases}\)
\(\Rightarrow\begin{cases}x=-5\\x=-6\end{cases}\)
(x+5)(x+6) = 0
=> x = 0 - 5
x = -5
=> x = 0 - 6
x = -6
vậy x = lần lượt là -5 ; -6