\(\left(x-1\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-1=0\\x+3=0\end{array}\right.\Leftrightarrow\left[\begin{array}{nghiempt}x=1\\x=-3\end{array}\right.\)
Vậy \(x\in\left\{1;-3\right\}\)
\(\left(x-4\right)\left(x+5\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-4=0\\x+5=0\end{array}\right.\Leftrightarrow\left[\begin{array}{nghiempt}x=4\\x=-5\end{array}\right.\)
Vậy \(x\in\left\{4;-5\right\}\)
\(\left(x-1\right)\left(x+3\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0+1\\x=0-3\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=1\\x=-3\end{array}\right.\)
\(\left(x-4\right)\left(x+5\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0+4\\x=0-5\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=4\\x=-5\end{array}\right.\)
1. ( x - 1 ) ( x + 3 ) = 0
\(\Rightarrow\) x - 1 = 0 hoặc x + 3 =0
x = 1 x = -3
Vậy x = 1 ; x = -3
2. (x - 4 ) ( x + 5 ) = 0
\(\Rightarrow\)x - 4 = 0 hoặc x + 5 = 0
x = 4 x = -5
Vậy x = 4 ; x = -5
( x - 1) ( x+ 3) = 0
TH1: ( x - 1) = 0 \(\Rightarrow\) x = 1
TH2 : (x - 3 ) = 0 \(\Rightarrow\) x = 3
( x - 4 ) ( x+ 5) =0
TH1: (x - 4) = 0 \(\Rightarrow\) x = 4
TH2: (x + 5) = 0 \(\Rightarrow\) x = -5
\(\left(x-1\right)\left(x+3\right)=0\)
\(\Rightarrow x-1=0\) hoặc \(x+3=0\)
+) \(x-1=0\Rightarrow x=1\)
+) \(x+3=0\Rightarrow x=-3\)
Vậy x = 1 hoặc x = -3
\(\left(x-4\right)\left(x+5\right)=0\)
\(\Rightarrow x-4=0\) hoặc \(x+5=0\)
+) \(x-4=0\Rightarrow x=4\)
+) \(x+5=0\Rightarrow x=-5\)
Vậy x = 4 hoặc x = -5