\(\Leftrightarrow\left(x-1\right)^{x+2}\left[\left(x-1\right)^2-1\right]=0\)
=>(x-1)(x-2)x=0
hay \(x\in\left\{0;1;2\right\}\)
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Tìm x.
\(1,\dfrac{3}{2}\left(x-\dfrac{1}{3}\right)-\dfrac{1}{2}\left(x+\dfrac{1}{2}\right)=\dfrac{1}{4}\)
\(2,3\left(x-2\right)-4\left(x+2\right)=x+2\)
\(3,4x\left(x-1\right)+4x-2\left(x+1\right)=-2\)
\(4,x\left(x+2\right)-3\left(x-1\right)=3\left(x+1\right)\)
tìm x biết :
\(\left|x-1\right|+2.\left|x-2\right|+3.\left|x-3\right|+4.\left|x-4\right|+5.\left|x-5\right|+20x=0\)
26 tháng 10 2021 lúc 12:36
Tìm x biết :
\(\left|x-\dfrac{1}{2}\right|+\left|x-\dfrac{1}{3}\right|+\left|x-\dfrac{1}{4}\right|+....+\left|x-\dfrac{1}{10}\right|=2x\)
a) Tìm tập hợp các số nguyên x, biết rằng4dfrac{5}{9}:2dfrac{5}{18}-7 x left(3dfrac{1}{5}:3,2+4,5.1dfrac{31}{45}right):left(-21dfrac{1}{2}right)b) tìm x, biết left|x+dfrac{1}{2}right|+left|x+dfrac{1}{6}right|+left|x+dfrac{1}{12}right|+left|x+dfrac{1}{20}right|+....+left|x+dfrac{1}{110}right|-11xc)Tính gt biểu thức C2x^3-5y^3+2015 tại x,y thỏa mãn left|x-1right|+left(y+2right)^{20}0
Đọc tiếp
a) Tìm tập hợp các số nguyên x, biết rằng\(4\dfrac{5}{9}:2\dfrac{5}{18}-7< x< \left(3\dfrac{1}{5}:3,2+4,5.1\dfrac{31}{45}\right):\left(-21\dfrac{1}{2}\right)\)
b) tìm x, biết \(\left|x+\dfrac{1}{2}\right|+\left|x+\dfrac{1}{6}\right|+\left|x+\dfrac{1}{12}\right|+\left|x+\dfrac{1}{20}\right|+....+\left|x+\dfrac{1}{110}\right|-11x\)
c)Tính gt biểu thức \(C=2x^3-5y^3+2015\) tại x,y thỏa mãn \(\left|x-1\right|+\left(y+2\right)^{20}=0\)
Tìm x biết : a) \(\left|x^3-x-1\right|=x^3+x+1\)
b) \(\left|x^4+x^2+1\right|=x^2-x-1\)
Tìm x:
\(3\left|x+4\right|-\left|2x+1\right|-5\left|x+3\right|+\left|x-9=5\right|\)
\(\left|x-2\right|+\left|x-3\right|+\left|2x-8\right|=9\\ \left|x+2\right|+\left|x+3\right|+\left|x+1\right|=4\\ \left|x+\dfrac{1}{1.5}\right|+\left|x+\dfrac{1}{5.9}\right|+\left|x+\dfrac{1}{9.13}\right|+...+\left|x+\dfrac{1}{397.401}\right|=101x\)
Tìm x, biết:
a) 4left|3x-1right|+left|xright|-2left|x-5right|+7left|x-3right|12
b) 3left|x+4right|-left|2x+1right|-5left|x+3right|+left|x+9right|5
c)
left|2frac{1}{5}-xright|+left|x-frac{1}{5}right|+8frac{1}{5}1,2
d) 2left|x+3frac{1}{2}right|+left|xright|-3frac{1}{2}left|2frac{1}{5}-xright|
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Tìm \(x,\) biết:
a) \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b) \(3\left|x+4\right|-\left|2x+1\right|-5\left|x+3\right|+\left|x+9\right|=5\)
c) \( \left|2\frac{1}{5}-x\right|+\left|x-\frac{1}{5}\right|+8\frac{1}{5}=1,2\)
d) \(2\left|x+3\frac{1}{2}\right|+\left|x\right|-3\frac{1}{2}=\left|2\frac{1}{5}-x\right|\)
\(tìmx\)
a,\(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
\(b,\left|x+1\right|+\left|x-2\right|+\left|x+3\right|=6\)
\(\left|\left(x+\dfrac{1}{2}\right)\backslash2x-\dfrac{3}{4}\ \right|=2x-\dfrac{3}{4}\)
Rút gọn biểu thức:
a, \(\left(2x+1\right)^2+\left(2x-1\right)^2-2\left(1+2x\right)\left(2x-1\right)\)
\(b,\left(x-1\right)^3-\left(x+2\right)\left(x^2-2x+4\right)+3\left(x-1\right)\left(x+1\right)\)
1. Tìm x, biết:
a) left|x-1right|+left|x-4right|5
b) 3left|x+4right|+left|x-5right|10
c) left|x+3right|+left|2x+1right|3x-6-left|x+1right|
d) left|xright|-left|2x+3right|left|x-1right|
e) left|x+1right|+left|2x-3right|left|3x-2right|
f) left|x+2right|+left|x+dfrac{3}{5}right|10x-left|x+dfrac{1}{2}right|
g) left|x+3right|+left|x+1right|3x
h) left|x-1right|+left|x-3right| x+1
i) left|x+dfrac{1}{1.3}right|+left|x+dfrac{1}{3.5}right|+...+left|x+dfrac{1}{97.99}right|50x
j) left|3x-5right|+l...
Đọc tiếp
1. Tìm x, biết:
a) \(\left|x-1\right|+\left|x-4\right|=5\)
b) \(3\left|x+4\right|+\left|x-5\right|=10\)
c) \(\left|x+3\right|+\left|2x+1\right|=3x-6-\left|x+1\right|\)
d) \(\left|x\right|-\left|2x+3\right|=\left|x-1\right|\)
e) \(\left|x+1\right|+\left|2x-3\right|=\left|3x-2\right|\)
f) \(\left|x+2\right|+\left|x+\dfrac{3}{5}\right|=10x-\left|x+\dfrac{1}{2}\right|\)
g) \(\left|x+3\right|+\left|x+1\right|=3x\)
h) \(\left|x-1\right|+\left|x-3\right|< x+1\)
i) \(\left|x+\dfrac{1}{1.3}\right|+\left|x+\dfrac{1}{3.5}\right|+...+\left|x+\dfrac{1}{97.99}\right|=50x\)
j) \(\left|3x-5\right|+\left|3x+1\right|=6\)
(Ai làm đc bài nào thì làm nha)