Question

Tìm x

\(\left|\dfrac{3}{4}-\dfrac{1}{2}x\right|+\dfrac{1}{3}=\dfrac{5}{6}\)

Answer 1

Giải:

\(\left|\dfrac{3}{4}-\dfrac{1}{2}x\right|+\dfrac{1}{3}=\dfrac{5}{6}\)

\(\Leftrightarrow\left|\dfrac{3}{4}-\dfrac{1}{2}x\right|=\dfrac{1}{2}\)

\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{3}{4}-\dfrac{1}{2}x=\dfrac{1}{2}\\\dfrac{3}{4}-\dfrac{1}{2}x=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x=\dfrac{1}{4}\\\dfrac{1}{2}x=\dfrac{5}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{5}{2}\end{matrix}\right.\)

Vậy \(x=\dfrac{1}{2}\) hoặc \(x=\dfrac{5}{2}\).

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