Ta có :
a) \(0,1x-\frac{1}{2}=0.75\Rightarrow0,1x=0,75+\frac{1}{2}=1,25\)
\(\Rightarrow x=1.25\div0.1=12.5\)
Vậy x = 12,5
b) l \(\frac{1}{3}-x\) l = 1
\(\Rightarrow\frac{1}{3}-x=1\) hoặc \(\frac{1}{3}-x=-1\)
\(\Rightarrow\) \(x=\frac{1}{3}-1=\frac{-2}{3}\) hoặc \(x=\frac{1}{3}-\left(-1\right)=\frac{4}{3}\)
Vậy \(x=\frac{-2}{3}\) hoặc \(x=\frac{4}{3}\)