Question

Tìm x :

\(\left(x^2+1\right).\left(x-1\right)=0\)

Answer 1

\(\left(x^2+1\right)\left(x-1\right)=0\)

\(\Rightarrow x^3-x^2+x-1=0\)

\(\Rightarrow x+x-1=0\)

\(\Rightarrow2x=1\)

\(\Rightarrow x=\frac{1}{2}\)

Answer 2

\(\left(x^2+1\right).\left(x-1\right)=0\)

\(\Rightarrow x^2+1=0\) hoặc \(x-1=0\)

TH1:\(x^2+1=0\)

       \(x^2=0+1\)

      \(x^2=1\)

\(\Rightarrow\)\(x=1\) hoặc \(x=-1\)

TH2:\(x-1=0\)

      \(x=0+1\)

      \(x=1\)

Vậy \(x=1\) hoặc \(x=-1\).