Question

tìm x biết

Answer 1

ta co : 2^3x+2 =4^x+5

^{\(\Rightarrow\)} 2^3x+2= (2²)^x+5\(\Rightarrow\)2^3x+2=2^2x+10

^{\(\Rightarrow\)}3x+2=2x+10

\(\Rightarrow\)3x-2x=8\(\Rightarrow\)x =8

Answer 2

Ta có: \(2^{3x+2}=4^{x+5}\)

\(\Rightarrow2^{3x+2}=\left(2^2\right)^{x+5}\)

\(\Rightarrow3x+2=2\left(x+5\right)\)

\(\Rightarrow3x+2=2x+10\)

\(\Rightarrow3x-2x=10-2\)

\(\Rightarrow x=8\)

Vậy: \(x=8\)

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