\(x^2=\frac{5}{7}x\)
\(\Rightarrow x^2-\frac{5}{7}x=0\)
\(\Rightarrow x.\left(x-\frac{5}{7}\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x-\frac{5}{7}=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=0+\frac{5}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\frac{5}{7}\end{matrix}\right.\)
Vậy \(x\in\left\{0;\frac{5}{7}\right\}.\)
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Ta có:
x2=\(\frac{5}{7}\)x
x=\(\frac{5}{7}\)
Vậy x=\(\frac{5}{7}\)