Ta có: \(\left(x-3\right)^2-3x+9=0\)
\(\Leftrightarrow\left(x-3\right)^2-3\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x-3-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=6\end{matrix}\right.\)
Vậy: \(x\in\left\{3;6\right\}\)
Bài 1: Tìm x biết a) x^3 - 4x^2 - x + 4= 0 b) x^3 - 3x^2 + 3x + 1=0 c) x^3 + 3x^2 - 4x - 12=0 d) (x-2)^2 - 4x +8 =0
Tìm x, biết:
2(x + 3) – x2 – 3x = 0
Bài 2 : Tìm x biết
a. 4x( x - 2 ) + x -2 = 0
b. ( 3x-1)2 - 9 = 0
c. x3 - 8 + ( x -2 ) ( x + 1 ) = 0
Tìm x biết :
a) 3x(x-1)+x-1=0
b) (x-2)(x2+2x+7+2(x2-4)-5(x-2)=0
c) (2x-1)2-25=0
d) x3+27+(x+3)(x-9)=0
Tìm x, biết :
3x^2 + 3x - 5(x+1) = 0
Tìm x , biết
a) 3x(x-1)+x-1=0
b) (x-2)(x2 +2x +7) +2 (x2 -4)-5(x-2)=0
c) ( 2x-1)2 -25=0
d) x3 +27 +(x+3)(x-9)
*mình cần gấp
Tìm x, biết:
a) x. (2x - 7) - 4x + 14 = 0
b) x2. (x - 1) - 4x + 4 = 0
c) x + x2 - x3 - x4 = 0
d) 2x3 + 3x2 + 2x + 3 = 0
e) 4x2 - 25 - (2x - 5). (2x + 7) = 0
g) x3 + 27 + (x + 3). (x - 9) = 0
tìm x
a, (x+3)^2 -x^2 +9 = 0
b, (x-2) (x^2+2)+(2-x)3x = 0
1, tìm x biết
a, (2x-1)^2-2x+1=0
b, (4x-3)^2-12x+9=0
c, 3x^2-48=0
tìm x , biết:
a)x^2 +5x+6=0
b) 2(x +3 )-x^2-3x =0
c) x^2 +4x +3 =0
d) x^2 - 3x +2 = 0
MIK CẦN GẤP!!!
