.
\(\left(4x-3\right)^2=\left(4x-3\right)\)
\(\Rightarrow\left(4x-3\right)^2-\left(4x-3\right)=0\)
\(\Rightarrow\left(4x-3\right)\left[\left(4x-3\right)-1\right]=0\)
\(\Rightarrow\left[{}\begin{matrix}4x-3=0\\4x-3-1=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}4x=3\\4x=4\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=1\end{matrix}\right.\)
\(x=1\) ,mò ra thôi chứ không biết giải thích.
\(\left(4x-3\right)^2=4x-3\)
\(\Leftrightarrow\left(4x-3\right)^2-\left(4x-3\right)=0\)
\(\Leftrightarrow\left(4x-3\right)^2.\left[\left(4x-2\right)^2-1\right]=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(4x-3\right)^2=0\\\left(4x-3\right)^2-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(4x-3\right)^2=0^2\\\left(4x-3\right)^2=1^2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}4x-3=0\\\left[{}\begin{matrix}4x-3=1\\4x-3=-1\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\\left[{}\begin{matrix}x=1\\x=\dfrac{1}{2}\end{matrix}\right.\end{matrix}\right.\)
Vậy ...
