\(\Leftrightarrow\frac{x-1001}{1006}-1+\frac{x-1003}{1004}-1+\frac{x-1005}{1002}-1+\frac{x-1007}{1000}-1=0\)
\(\Leftrightarrow\frac{x-2007}{1006}+\frac{x-2007}{1004}+\frac{x-2007}{1002}+\frac{x-2007}{1000}=0\)
\(\Leftrightarrow\left(x-2007\right)\left(\frac{1}{1006}+\frac{1}{1004}+\frac{1}{1002}+\frac{1}{1000}\right)=0\)
\(\Leftrightarrow x=2007\)
Giải phương trình:
x-1001/1006 + x-1003/1004 + x-1005/1002 + x-1007/1000 = 4
giải hương trình:\(\dfrac{x-1001}{1006}+\dfrac{x-1003}{1004}+\dfrac{x-1005}{1002}+\dfrac{x-1007}{1000}\)=4
\(\frac{x-1003}{1007}+\frac{x-4}{1003}+\frac{x+2010}{1005}=7\)
Everybody =) Help me.
Let be given an open interval\(\left(\alpha;eta\right)\) with \(eta-\alpha=\frac{1}{2007}.\)Determine the maximum number of irreducible fractions \(\frac{a}{b}\) in \(\left(\alpha;eta\right)\) with \(1\le b\le2007?\)
A) 1002
b) 1003
C) 1004
D)1005
E)1006
Giải các phương trình và bất phương trình sau:
a) \(\frac{x-1}{2015}+\frac{x}{2014}+\frac{2}{1006}=\frac{x-3}{2013}+\frac{x}{2012}+\frac{1}{1007}\)
b)\(\frac{4}{1+y+y^2}+\frac{1}{1-y}\le\frac{2y^2-5}{y^3-1}\)
LÀM ƠN HÃY GIÚP MK=333
X-1009/1001+x-4/1003+x+2010/1005=7
Chứng minh các hằng đẳng thức sau :
a, \(\left(a^2-b^2\right)+\left(2ab\right)^2=\left(a^2+b^2\right)^2\)
b, \(\left(a^2+b^2\right).\left(c^2+d^2\right)=\left(ac+bd\right)^2+\left(ad-bc\right)^2\)
c, \(\left(ax+b\right)^2+\left(a-bx\right)^2+c^2x^2=\left(a^2+b^2+c^2\right).\left(x^2+1\right)\)
d, \(\dfrac{1}{2}.\left(a+b+c\right).\left[\left(a-b\right)^2+\left(b-c\right)^2+\left(c-a\right)^2\right]=a^3+b^3+c^3-3abc\)
e, \(1000^2+1003^2+1005^2+1006^2=1001^2+1002^2+1004^2+1007^2\)
giải pt sau: \(\frac{x-1009}{1010}+\frac{x-1007}{1012}=\frac{x-1010}{1009}+\frac{x-1012}{1007}\)
giải pt sau: \(\frac{x-1009}{1010}+\frac{x-1007}{1012}=\frac{x-1010}{1009}+\frac{x-1012}{1007}\)
x-1009/ 1001 + x - 14/ 1003 + x - 2000/ 1005 = 7
