\(3\left|x\right|-x=12\)
\(\Rightarrow3x-x=12\)
\(\Rightarrow x\left(3-1\right)=12\)
\(\Rightarrow2x=12\)
\(\Rightarrow x=6\)
Vậy......
ta có 3.|x| - x = 12
⇒ \(\left[{}\begin{matrix}-3x-x=12\\3x-x=12\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}-4x=12\\2x=12\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-3\\x=6\end{matrix}\right.\)
vậy x ∈ {-3;6}