\(\Rightarrow2x\left(x-2\right)+3\left(x-2\right)=0\Rightarrow\left(x-2\right)\left(2x+3\right)=0\Rightarrow\left[{}\begin{matrix}x=2\\x=-\dfrac{3}{2}\end{matrix}\right.\)
2x(x-2)+3(x-2)=0
(x-2)(2x+3)=0
x-2=0 hay 2x+3=0
x=2 hay 2x=-3
x=2 hay x= -\(\dfrac{3}{2}\)
2x2 - 4x + 3x - 6 = 0
( x - 2 ) ( 2x + 3 ) = 0
\(\left\{{}\begin{matrix}x-2=0\\2x+3=0\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}x=2\\x=\dfrac{-3}{2}\end{matrix}\right.\)
\(2x^2-4x+3x-6=0\Leftrightarrow2x^2-x-6=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{-3}{2}\end{matrix}\right.\)