\(\frac{2x+3}{5x+2}=\frac{4x+5}{10x+2}\)
\(\Leftrightarrow2x.\left(10x+2\right)+3.\left(10x+2\right)=5x.\left(4x+5\right)+2.\left(4x+5\right)\)
\(\Leftrightarrow20x^2+4x+30x+6=20x^2+25x+8x+10\)
\(\Leftrightarrow34x+6=33x+10\)
\(\Leftrightarrow34x-33x=10-6\)
\(\Rightarrow x=4\)
Vậy : \(x=4\)
\(\frac{2x+3}{5x+2}=\frac{4x+5}{10x+2}\)
⇒ \(\left(2x+3\right).\left(10x+2\right)=\left(4x+5\right).\left(5x+2\right)\)
⇒ \(20x^2+4x+30x+6=20x^2+8x+25x+10\)
⇒ \(20x^2+4x+30x+6-20x^2-8x-25x-10=0\)
⇒ \(1x-4=0\)
⇒ \(1x=0+4\)
⇒ \(1x=4\)
⇒ \(x=4:1\)
⇒ \(x=4\)
Vậy \(x=4.\)
Chúc bạn học tốt!
\(\frac{2x+3}{5x+2}\) = \(\frac{4x+5}{10x+2}\)
<=> \(\frac{4x+6}{10x+4}\) = \(\frac{4x+5}{10x+2}\)
Áp dụng t.c của dãy tỉ số bằng nhau, ta có:
\(\frac{4x+6}{10x+4}\) = \(\frac{4x+5}{10x+2}\) = \(\frac{4x+6-4x-5}{10x+4-10x-2}\) = \(\frac{1}{2}\)
=> 4 x + 6 = \(\frac{1}{2}\) . ( 10x +4 )
=>4x + 6 = 5x + 2
=> x= 6 - 2
=> x =4
