\(2x^2-3\left(1-x\right)\left(x+1\right)=5x\left(x+1\right)\\ \Leftrightarrow2x^2+3\left(x^2-1\right)=5x^2+5x\\ \Leftrightarrow2x^2+3x^2-3=5x^2+5x\\ \Leftrightarrow x=-\dfrac{3}{5}\\ \Rightarrow S=\left\{-\dfrac{3}{5}\right\}\)
Ta có: \(2x^2-3\left(1-x\right)\left(x+1\right)=5x\left(x+1\right)\)
\(\Leftrightarrow2x^2+3x^2-3-5x^2-5x=0\)
\(\Leftrightarrow-5x=3\)
hay \(x=-\dfrac{3}{5}\)