(1−2x)3=27
(1−2x)3=33
1-2x=3
2x=1-3
2x=-2
x=(-2):2
x=-1
Vậy x=-1
( 1 - 2x ) 3 = 27
( 1 - 2x )3 = 33
\(\Rightarrow\) 1 - 2x = 3
2x = 1 - 3
2x = -2
x = -2 : 2
x = -1
(1−2x)3=27
(1−2x)3=33
1-2x=3
2x=1-3
2x=-2
x=(-2):2
x=-1
Vậy x=-1
( 1 - 2x ) 3 = 27
( 1 - 2x )3 = 33
\(\Rightarrow\) 1 - 2x = 3
2x = 1 - 3
2x = -2
x = -2 : 2
x = -1
1)tìm x biết:
a)(x-2)^2=1
b)(2x-1)^3=-8
c)(x+1/2)^2=1/16
d)(x-2)^3=-27
e(2x-3)^2=25
g)3^x-1=1/243
h)2^x+2^x+3=144
k)81^-2x*27^x=95
tìm x biết
a) ( 2x+3)^2=9/121
b) (3x-1)^3= -8/27
1)tìm x biết:
a)(x-2)^2=1
b)(2x-1)^3=-8
c)(x+1/2)^2=1/16
d)(x-2)^3=-27
e(2x-3)^2=25
g)3^x-1=1/243
h)2^x+2^x+3=144
k)81^-2x*27^x=95
Tìm x biết:
1) | 2x-1| = -19 -x
2) | 4- 3x| = 2x- 10
3) | x| = 3+ 2x
Tìm x biết:
1) | 2x-1| = -19 -x
2) | 4- 3x| = 2x- 10
3) | x| = 3+ 2x
Tìm x, biết:
a, ( x - 1/2 ) mũ 3 = 1/27
b, ( x + 1/2 ) mũ 2 = 4/25
a ) Tìm x biết : | 2x - 2 | = | 2x + 3 |
b ) Tìm GTLN của A = \(\frac{1}{\sqrt{x-2}+3}\)
c ) Tìm x để : \(\frac{2x+1}{x-2}< 2\)
Tìm x, biết: |2x+1|=x-3
Tìm x biết:
a) (2x+1)^5= (2x+1)
b) |2-5x|=|x+1|
c) |x-3|+(x^2 -9)^2=0
d) |4x+1| -2x+3=5
Tìm x, biết:
a. \(\left(2x-3^2\right)=25\)
b. \(\dfrac{27}{3^x}=3\)
c. \(9^{x-1}=\dfrac{1}{9}\)
d. \(3^{x+1}+3^{x+3}=810\)