Question

tìm x

a,(x + 15):x = 4:3

b,(7,5 - x) : ( 3,5 + x) = 5 : 6

c,(x - 20) : (x - 10) = (x + 40) : (x + 70)

Answer 1

\(a,\left(x+15\right):x=4:3\)

=>\(1+\dfrac{15}{x}=\dfrac{4}{3}\)

=>\(\dfrac{15}{x}=\dfrac{1}{3}\)

=>\(x=3.15=45\)

Vậy x=45

b)\(\dfrac{7,5-x}{3,5+x}=\dfrac{5}{6}\)

\(6\left(7,5-x\right)=5\left(3,5+x\right)\)

=>\(45-6x=17,5+5x\)

=>\(-11x=-27,5\)

=>\(x=2,5\)

Vậy...

c)\(\dfrac{x-20}{x-10}=\dfrac{x+40}{x+70}\)

=>\(\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)

=>\(x^2+50x-140=x^2+30x-40\)

=>\(20x=100\)

=>\(x=50\)