Question

Tìm x:

1/ \(\dfrac{3}{2}x-\dfrac{2}{5}=\dfrac{1}{3}x-\dfrac{1}{4}\)

Answer 1

\(\dfrac{3}{2}x-\dfrac{2}{5}=\dfrac{1}{3}x-\dfrac{1}{4}\)

\(\dfrac{3}{2}x-\dfrac{1}{3}x=-\dfrac{1}{4}+\dfrac{2}{5}\)

\(\left(\dfrac{3}{2}-\dfrac{1}{3}\right)x=\dfrac{3}{20}\)

\(\dfrac{7}{6}x=\dfrac{3}{20}\)

\(x=\dfrac{9}{70}\)

Answer 2

\(\dfrac{3}{2}x-\dfrac{2}{5}=\dfrac{1}{3}x-\dfrac{1}{4}\)
\(\dfrac{3}{2}x-\dfrac{1}{3}x=-\dfrac{1}{4}+\dfrac{2}{5}\)
\(x\left(\dfrac{3}{2}-\dfrac{1}{3}\right)=\dfrac{3}{20}\)
\(\dfrac{7}{6}x=\dfrac{3}{20}\)
\(x=\dfrac{3}{20}:\dfrac{7}{6}\)
\(x=\dfrac{9}{70}\)

\(\)Vậy \(x=\dfrac{9}{70}\)